
In a message dated 10/20/2000 6:58:28 AM Pacific Daylight Time, raphiem@onebox.com writes:
<< now i did the same to see what the min.arc harmonic was from the France location to the prime meridian (Gizah Pyramid) 29d 58m 53s N and
31d 8m 0.8s E
i calculate 1506.89 (round up 1507) now i didn't get anywhere with 1507 i could force/play withthe numbers tomake them look good ... but then that would not be right ..
Michael L ... have a crack at it .. >> 
Very good, Raphiem !!! Well ... when I see "1507" ... I do think of the "48 X Pi" decimal harmonic. And "48" is "6 X 8" ... or ... "6 X (2 Cubed)". The "Cubing
of 2" is kind of a 'metaphor' for the "epitome of a Cube" ... each of the *6* equal sides of a Cube ("3D" reality metaphor ?) have "2D" length and width that are equal. And
then, you're multiplying the "Cube" by 6.
(480 X 3.141592654) = 1507.964474 ... which I can think of as the first "step" toward the Orion beltstar MINTAKA. Recall, here, that Dan Winter wrote
a recent article .. posted to (I think) both MissionIgnition and to GeneofIsis (lists) in which he quoted a certain source (can't recall the name of the source) that refers to a "StarBase One"
on "Telos", in the MINTAKA system. Could that really be true ? Hmmmm. I wonder.
With that in mind, I now multiply twice more by Pi ... (1507.964474 X Pi X Pi) = 14883.01281 ... which I recognize
as the Grid LONG (W.Giza) of "The Old Man of The Mountain" in New Hampshire, USA. Munck (1992) decoded this granite profileeffigy of a human face, which is located on the side of Cannon Mountain.
14883.01281 W.Giza ... = 102 (deg) X 49 (min) X 2.977793679 (sec) W.Giza. [ W.Greenwich 71 deg 41 min 2.177793679 sec ].
And Raphiem mentions Stonehenge, above. Notice how "The Old Man" is very much "aware" of the Sarsen Circle dimensions of Stonehenge : (48.66934411 X 305.7985079) = 14883.01281 .. that 'Old
Man' must have quite a memory !!!
And .. he knows those Sarsen Circle dimensions in *regular British feet*.
Notice that I multiplied that "1507.964474" by Pi .. 3 times .. So .. I multiplied by
the "Cube of Pi". I found (Pi Cubed) to be the Grid POINT Value for the Orion beltstar MINTAKA .. please see ..
http://www.topcities.com/OuterSpace/farshores/farshores/skymat_1.htm Or ... you
can find it on the MissionIgnition site, right, Raphiem ? I don't have the URL handy, but maybe Raphiem can post it ... (;
If I multiply the Old Man's Grid LONG by Pi again ... 14883.01281 X 3.141592654 = 46756.36371 .. the Grid LAT of the Mycerinus Pyramid of GIZA !!! (Munck, 1992). 14883.01281 North .. = 29 (deg) X 58 (min) X
27.79807593 (sec) North.
And many of you know that Robert Bauval noticed that the 3 Orion beltstars are represented by the 3 main pyramids at Giza. And ... MINTAKA corresponds to ... the Mycerinus Pyramid !!
Munck also noticed that the very slope angle of both the Mycerinus Pyramid and The Great Pyramid .. they have identical slope angles ... 51.853974 (deg) from their bases ... encode the Grid LAT of the Mycerinus
Pyramid at the *top* of the slope !! The slope angle at the top is ... 128 (deg) X 08 (min) X 45.66051144 (sec) ... = 46756.36371
So .. the Old Man knows the Pi constant .. and he knows something about what's at Giza !!
Regarding the France Location ...
<< Subj: [MI] TX40 and 144 light harmonic
Date: 10/20/2000 6:58:28 AM Pacific Daylight Time From: raphiem@onebox.com (Raphiem) Replyto: missionignition@topica.com
To: raphiem@onebox.com
many have probably come across the following site ...http://www.tx40.net/html/indexes/index_uk.html where they go on about planetary contact on Oct 25
etc,etc did a little digging and found that the above site was hosted on a server in france ... and registered to a company called "toys international" well the latest update they give a location of where the
antenna is situated, where they will receive contact ... check the site out if you already haven't anyway the long/lats coords they give are 45°50.765 N, 6°09.098 E mapping this works out somewhere in france, around
Meribel could it be where the toy factory is ?? ;o)) anyway i thought since they gave some numbers i'd have a little play (couldn't help myself) now i did not use Munck/Morton Matrix calcs, as i thought i'd leave this
for Michael L ... to have a go ... but i used Bruce Cathie grid harmonics ... minutes.arc from the above location to StoneHenge (51d 10m 42s N and 1d 49m 28s W) works out to be 449.92 mins.arc lets round it up to
450min.arc now watch when i raise the above by 6 (60) which is the angular rotation octave cycle 450 x 6 = 2700 another octave 2700 x 6 = 16200 or 450 x 36 = 16200
162 is the speed of light harmonic as it
enters gravity forming matter if we adjust this as per Bruce Cathie's time grid which is made up of 27hours in one rotation i.e. 1hr = 0.88 hr grid harmonic thus 162 x 24 / 27 = 144!!!!!!! (half light) 288 is full light
>> { Or; some say 144 is 'light' and 288 is 'doublelight' }
 MLM 
OK ... let's take a look at these coordinates quoted by Raphiem ... 45°50.765 N,
6°09.098 E 0.765 X 60 = 45.9 arcseconds. So ... 45 (deg) X 50 (min) X 45.9 (sec) = 103275 North (approx.) That's an approximation for the Grid LAT.
The closest "archaeosky matrix" figure to that, as
far as I know, is .. a decimal harmonic of .. what Munck (1992) found to be .. the Old Man's Grid POINT Value (1.033542556) !!!
To show you the truth of this, here is the Old Man's Grid LAT .. 44 (deg) X 09 (min) X 38.84400782 (sec) North ..
= 15382.2271 North. (Munck, 1992). And the Grid POINT Value of "The Old Man of the Mountain" .. 15382.2271 / 14883.01281 = 1.033542556
Our Grid LAT for the location in France would be .. 103354.2556
North .. = 45 (deg) X 50 (min) X 45.93522471 (sec) North.
This is only about 0.05 arcseconds north, at most, of the approximation of "45.9" arcsec. So ... this is only roughly 5 feet, or less,
of difference from the approximation.
Now ... for the Grid LONG ... first in E.Greenwich format ... 0.098 X 60 = 5.88 (sec) approx. So ... now we convert to W.Giza longitude ... 31 deg 08 min 0.80 sec 06
" 09 " 5.88 "  24 deg 58 min 54.92 sec .. approx.
24 (deg) X 58 (min) X 54.92 (sec) = 76448.64 W.Giza, approx.
Here, I do recognize a *very close*
decimal harmonic approximation to .. Stonehenge Grid POINT Value (Munck, 1992) .. times .. Pi.
Stonehenge Grid POINT Value = 2.433467206 .. times Pi .... 3.141592654 X 2.433467206 = 7.644962697 ..
So .. the Grid LONG W.Giza would be ... 76449.62697 W.Giza .. = 24 (deg) X 58 (min) X 54.92070903 (sec) W.Giza. [ E.Greenwich 06 deg 09 min 05.87929097 sec ].
Now .. the Grid POINT Value ... we take the ratio .... 103354.2556 / 76449.62697 = 1.351926225
Yes .. I do recognize this figure .. as a Pistep away from the ratio of the archaeosky matrix formats of 2 very
important angles ... 51.853974 (deg) and 19.47122061 (deg). Respectively, those angles are : the base slope angle of both the Mycerinus Pyramid and The Great Pyramid of Giza, and the (Hoagland) "Tetrahedral
Latitude" north/south from planetary equators.
51.853974 (deg) ... transforms into .. 51 (deg) X 51 (min) X 14.30508728 (sec) .. = 37207.53202
19.47122061 (deg) .. which has a Sine of exactly
"1/3rd" .. transforms into .. 19 (deg) X 28 (min) X 16.46707132 (sec) north/south .. = 8760.481942 ... North/South, from planetary equators. This involves the basis of R.C. Hoagland's "hyperdimensional
physics" model .. 2 tetrahedra inscribed within a sphere, with one corner of each tetrahedron touching at opposite planetary poles.
Using the Pi constant .. 37207.53202 / 1.351926225 / 3.141592654 = 8760.481942
I would say that this "specified" location .. given by those coordinates as reported by Raphiem (in his email) ..
appears to be quite "intelligentlydetermined", and seemingly "aware" of some important aspects of this 'archaeosky matrix'.
And, you know .. I just can't say enough about the Old Man !!! He
knows that slope angle of the Mycerinus Pyramid and The Great Pyramid ... from toptobottom. (;
 Michael Lawrence Morton

